Загрузка изображения на сервер — Android

В настоящее время я использую этот код для загрузки небольших видео на сервер (на стороне сервера PHP).

Не думайте, что apache HttpClient больше не поддерживается, поэтому HttpURLConnection — это то, что вам нужно.

    try {
        FileInputStream fileInputStream = new FileInputStream(new File(
                path));

        URL url = new URL(urlLink);
        connection = (HttpURLConnection) url.openConnection();

        connection.setDoInput(true);
        connection.setDoOutput(true);
        connection.setUseCaches(false);

        connection.setRequestMethod("POST");

        connection.setRequestProperty("Connection", "Keep-Alive");
        connection.setRequestProperty("Content-Type",
                "multipart/form-data;boundary=" + boundary);

        outputStream = new DataOutputStream(connection.getOutputStream());
        outputStream.writeBytes(twoHyphens + boundary + lineEnd);
        outputStream
                .writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\""
                        + path + "\"" + lineEnd);
        outputStream.writeBytes(lineEnd);

        bytesAvailable = fileInputStream.available();
        bufferSize = Math.min(bytesAvailable, maxBufferSize);
        buffer = new byte[bufferSize];

        bytesRead = fileInputStream.read(buffer, 0, bufferSize);

        while (bytesRead > 0) {
            outputStream.write(buffer, 0, bufferSize);
            bytesAvailable = fileInputStream.available();
            bufferSize = Math.min(bytesAvailable, maxBufferSize);
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);
        }

        outputStream.writeBytes(lineEnd);
        outputStream.writeBytes(twoHyphens + boundary + twoHyphens
                + lineEnd);

        fileInputStream.close();
        outputStream.flush();
        outputStream.close();

        InputStream responseStream = new BufferedInputStream(connection.getInputStream());

        BufferedReader responseStreamReader = new BufferedReader(new InputStreamReader(responseStream));
        String line = "";
        StringBuilder stringBuilder = new StringBuilder();
        while ((line = responseStreamReader.readLine()) != null) {
            stringBuilder.append(line).append("\n");
        }
        responseStreamReader.close();

        String response = stringBuilder.toString();
        Log.w("SERVER RESPONE: ", response);

        responseStream.close();
        connection.disconnect();

    } catch (Exception ex) {
        Log.i("UPLOAD ERROR", "ERROR ERROR");
    }
}

вот PHP, который может помочь вам получить файл на вашем сервере.

<?php

try {


    // Checking for upload attack and rendering invalid.
    if (
        !isset($_FILES['uploadedfile']['error']) ||
        is_array($_FILES['uploadedfile']['error'])
    ) {
        throw new RuntimeException('Invalid parameters.');
    }

    // checking for error value on upload
    switch ($_FILES['uploadedfile']['error']) {
        case UPLOAD_ERR_OK:
            break;
        case UPLOAD_ERR_NO_FILE:
            throw new RuntimeException('No file sent.');
        case UPLOAD_ERR_INI_SIZE:
        case UPLOAD_ERR_FORM_SIZE:
            throw new RuntimeException('Exceeded filesize limit.');
        default:
            throw new RuntimeException('Unknown errors.');
    }

    // checking file size 
    if ($_FILES['uploadedfile']['size'] > 1000000) {
        throw new RuntimeException('Exceeded filesize limit.');
    }


    // checking MIME type for mp4... change this to suit your needs
    $finfo = new finfo(FILEINFO_MIME_TYPE);
    if (false === $ext = array_search(
        $finfo->file($_FILES['uploadedfile']['tmp_name']),
        array(
            'mp4' => 'video/mp4',
        ),
        true
    )) {
        throw new RuntimeException('Invalid file format.');
    }


    // Uniquely naming each uploaded for file
    if (!move_uploaded_file(
        $_FILES['uploadedfile']['tmp_name'],
        sprintf('./uploads/%s.%s',
            sha1_file($_FILES['uploadedfile']['tmp_name']),
            $ext
        )
    )) {
        throw new RuntimeException('Failed to move uploaded file.');
    }
    // response code.
    echo 'File is uploaded successfully!';

}
catch (RuntimeException $e) {

    echo $e->getMessage();

}

?>

попробуй это....

public static JSONObject postFile(String url,String filePath,int id){

String result="";
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);

File file = new File(filePath);
MultipartEntity mpEntity = new MultipartEntity();
ContentBody cbFile = new FileBody(file, "image/jpeg");

StringBody stringBody= null;
JSONObject responseObject=null;

try {
    stringBody = new StringBody(id+"");
    mpEntity.addPart("file", cbFile);
    mpEntity.addPart("id",stringBody);
    httpPost.setEntity(mpEntity);
    System.out.println("executing request " + httpPost.getRequestLine());
    HttpResponse response = httpClient.execute(httpPost);
    HttpEntity resEntity = response.getEntity();
    result=resEntity.toString();
    responseObject=new JSONObject(result);
} 
catch (UnsupportedEncodingException e) {
    e.printStackTrace();
} 
catch (ClientProtocolException e) {
    e.printStackTrace();
} 
catch (IOException e) {
    e.printStackTrace();
} 
catch (JSONException e) {
    e.printStackTrace();
}
return responseObject;
}